Both numbers must be <= 1.
Which ages do you choose?

Fuck this is hard! I must take time to ponder...

Okay. Considering that I would take no joy what so ever banging kids under the age of 13, I might as well gain some reward for my suffering. A 1 year old would be too difficult to handle so I might as well bump it up to 2. I might go with 3, but I don't see a difference between 3 and 2 so I might as well get a bonus age. 2 and 18 is my end choice.

13 and 7, city kids, their probably fucking prostitutes already, well, at least in mish/des australia/victoria.

I'd have to go with 1 and 19. Hopefully the 1-year-old wouldn't remember anything or be scarred for life.

i think i'd just end up rolling with whatever consequences i get for not doing it, no way i'm putting my dick in a kid

Quote from Chunky

i think i'd just end up rolling with whatever consequences i get for not doing it, no way i'm putting my dick in a kid

i like the way you think

11 and 9. too easy

You didn't specify *years* in the thread title or your original post, so I'll just assume that you mean increments of 2 years. Which means 2 20 year olds.

Quote from Fusion

You didn't specify *years* in the thread title or your original post, so I'll just assume that you mean increments of 2 years. Which means 2 20 year olds.

he said sum to 20, so unless you're banging a 20 + a 40 year old that won't work i believem

If x=2, then 10x=20
And 10+10 is also 20. Two people that have the age of 10 in increments of two years are both twenty.

WAIT.
Idea.
One 20 year old.
and one 0 year old. That does not exist yet.

Problem?

Yes, in the original post it says their respective ages must be equal to or greater than 1.

Quote from Fusion

Yes, in the original post it says their respective ages must be equal to or greater than 1.

Me no can reading engrish.

learn like me

same as fusion