muttonhead, why do u post things tht puzzle your feeble mind?
every1 thinks....knows your a dumma$$
Test your logic
Started by: ßub | Replies: 50 | Views: 2,599
Mar 26, 2008 6:04 AM #102016
Mar 26, 2008 6:10 AM #102024
Quote from the afro ninjamuttonhead, why do u post things tht puzzle your feeble mind?
every1 thinks....knows your a dumma$$
Shut up stupid noob. Spell things right and say "dumbass" not dumba$$, it makes you look like a douche bag.
Mar 26, 2008 6:47 AM #102039
trying not to get it cencorsed ****ing dumbass cunt bitch ****er kike dick blowing shit hole of cum, seriously you're pissing me off, leave me alone and ill leave u alone
Mar 26, 2008 4:42 PM #102319
Quote from the afro ninjatrying not to get it cencorsed ****ing dumbass cunt bitch ****er kike dick blowing shit hole of cum, seriously you're pissing me off, leave me alone and ill leave u alone
AHAHAHAHAH HAHAHAHAH
Noobs these days, they think they have power over people.
Mar 28, 2008 5:12 AM #104030
Quote from the afro ninjamuttonhead, why do u post things tht puzzle your feeble mind?
every1 thinks....knows your a dumma$$
haha. Somebody wants attention..
Mar 30, 2008 4:34 AM #105602
Bayes' theorem
An analysis of the problem using the formalism of Bayesian probability theory (Gill 2002) makes explicit the role of the assumptions underlying the problem. In Bayesian terms, probabilities are associated to propositions, and express a degree of belief in their truth, subject to whatever background information happens to be known. For this problem the background is the set of game rules, and the propositions of interest are:
: The car is behind Door i, for i equal to 1, 2 or 3.
: The host opens Door j after the player has picked Door i, for i and j equal to 1, 2 or 3.
For example,
denotes the proposition the car is behind Door 1, and
denotes the proposition the host opens Door 2 after the player has picked Door 1. Indicating the background information with
, the assumptions are formally stated as follows.
First, the car can be behind any door, and all doors are a priori equally likely to hide the car. In this context a priori means before the game is played, or before seeing the goat. Hence, the prior probability of a proposition
is:

Second, the host will always open a door that has no car behind it, chosen from among the two not picked by the player. If two such doors are available, each one is equally likely to be opened. This rule determines the conditional probability of a proposition
subject to where the car is — i.e., conditioned on a proposition
. Specifically, it is:

The problem can now be solved by scoring each strategy with its associated posterior probability of winning, that is with its probability subject to the host's opening of one of the doors. Without loss of generality, assume, by re-numbering the doors if necessary, that the player picks Door 1, and that the host then opens Door 3, revealing a goat. In other words, the host makes proposition H_{13}\, true.
The posterior probability of winning by not switching doors, subject to the game rules and H_{13}\,, is then P(C_1 | H_{13},\,I). Using Bayes' theorem this is expressed as:
By the assumptions stated above, the numerator of the right-hand side is:
The normalizing constant at the denominator can be evaluated by expanding it using the definitions of marginal probability and conditional probability:

Dividing the numerator by the normalizing constant yields:
Note that this is equal to the prior probability of the car's being behind the initially chosen door, meaning that the host's action has not contributed any novel information with regard to this eventuality. In fact, the following argument shows that the effect of the host's action consists entirely of redistributing the probabilities for the car's being behind either of the other two doors.
The probability of winning by switching the selection to Door 2,
can be evaluated by requiring that the posterior probabilities of all the
propositions add to 1. That is:

There is no car behind Door 3, since the host opened it, so the last term must be zero. This can be proven using Bayes' theorem and the previous results:

Hence:

This shows that the winning strategy is to switch the selection to Door 2. It also makes clear that the host's showing of the goat behind Door 3 has the effect of transferring the 1/3 of winning probability a-priori associated with that door to the remaining unselected and unopened one, thus making it the most likely winning choice.
i cant be stuffed adding all the pictures, so get over it.
An analysis of the problem using the formalism of Bayesian probability theory (Gill 2002) makes explicit the role of the assumptions underlying the problem. In Bayesian terms, probabilities are associated to propositions, and express a degree of belief in their truth, subject to whatever background information happens to be known. For this problem the background is the set of game rules, and the propositions of interest are:


For example,



First, the car can be behind any door, and all doors are a priori equally likely to hide the car. In this context a priori means before the game is played, or before seeing the goat. Hence, the prior probability of a proposition


Second, the host will always open a door that has no car behind it, chosen from among the two not picked by the player. If two such doors are available, each one is equally likely to be opened. This rule determines the conditional probability of a proposition



The problem can now be solved by scoring each strategy with its associated posterior probability of winning, that is with its probability subject to the host's opening of one of the doors. Without loss of generality, assume, by re-numbering the doors if necessary, that the player picks Door 1, and that the host then opens Door 3, revealing a goat. In other words, the host makes proposition H_{13}\, true.
The posterior probability of winning by not switching doors, subject to the game rules and H_{13}\,, is then P(C_1 | H_{13},\,I). Using Bayes' theorem this is expressed as:
By the assumptions stated above, the numerator of the right-hand side is:
The normalizing constant at the denominator can be evaluated by expanding it using the definitions of marginal probability and conditional probability:

Dividing the numerator by the normalizing constant yields:
Note that this is equal to the prior probability of the car's being behind the initially chosen door, meaning that the host's action has not contributed any novel information with regard to this eventuality. In fact, the following argument shows that the effect of the host's action consists entirely of redistributing the probabilities for the car's being behind either of the other two doors.
The probability of winning by switching the selection to Door 2,



There is no car behind Door 3, since the host opened it, so the last term must be zero. This can be proven using Bayes' theorem and the previous results:

Hence:

This shows that the winning strategy is to switch the selection to Door 2. It also makes clear that the host's showing of the goat behind Door 3 has the effect of transferring the 1/3 of winning probability a-priori associated with that door to the remaining unselected and unopened one, thus making it the most likely winning choice.
i cant be stuffed adding all the pictures, so get over it.
Mar 30, 2008 10:38 AM #105774
wiki get?
Mar 30, 2008 2:03 PM #105815
There was a game show like this.
Mar 31, 2008 9:54 AM #106535
Quote from the Jawzwiki get?
indeed =P
Apr 1, 2008 1:18 AM #106954
Quote from Brian CAHAHAHAHAH HAHAHAHAH
Noobs these days, they think they have power over people.
you're a noob, **** off
Apr 1, 2008 1:20 AM #106955
Quote from Setminyou're a noob, **** off
seth am i a noob
Apr 1, 2008 1:24 AM #106958
Quote from paganseth am i a noob
nope : )
Apr 1, 2008 1:26 AM #106960
You get 2/3 if your counting consecutive. But if you have a car behind one door, and a goat behind another, its a 1/2 chance.
mutton, why the hell do you post this shit?
mutton, why the hell do you post this shit?
Apr 1, 2008 1:26 AM #106961
Hi setmin :Smile:
Apr 1, 2008 1:29 AM #106962
Quote from ApplesHi setmin :Smile:
hey dude sup long time no see