0.33 recurring is 1/3
0.66 recurring is 2/3
and 0.99 recurring is 3/3.
therefore 0.99 recurring = 1?
Maths
Started by: flamingemu | Replies: 17 | Views: 1,479
Jun 23, 2009 5:55 PM #446462
Jun 23, 2009 7:24 PM #446519
if you rounded up, sure.
Jun 23, 2009 7:26 PM #446523
Are you a calculator.
.33 recurring is used to write down 1/3
.66 recurring is used to write down 2/3
And 1 is used to write down 3/3
It's impossible otherwise.
/thread
.33 recurring is used to write down 1/3
.66 recurring is used to write down 2/3
And 1 is used to write down 3/3
It's impossible otherwise.
/thread
Jun 23, 2009 7:30 PM #446528
jeez, this has been asked many times.
0.99 recurring is as close to 1 as physically possible, and even more than that, so in relative terms: Yes, 0.99 recurring = 1.
0.99 recurring is as close to 1 as physically possible, and even more than that, so in relative terms: Yes, 0.99 recurring = 1.
Jun 23, 2009 9:06 PM #446587
In math, .99 recurring is 1. It is accepted.
Jun 23, 2009 9:44 PM #446609
****en learn to maths
Jun 24, 2009 1:05 AM #446744
.99 repeating is 1. This is proven by the fact that when subtracted, the numbers have no "difference".
Jun 24, 2009 1:34 AM #446759
.9 = 9/10
.09 = 9/100
.009 = 9/1000
... etc.
.9999999... = 9/10 + 9/100 + 9/1000 + ...
.09 = 9/100
.009 = 9/1000
... etc.
.9999999... = 9/10 + 9/100 + 9/1000 + ...
Jun 24, 2009 5:50 AM #446842
Quote from Ash.99 repeating is 1. This is proven by the fact that when subtracted, the numbers have no "difference".
that fact only holds true if we agree that .9999999... is one. so I don't think that really proves anything.
That said, I agree with you. It is generally agreed upon in the mathematic community that .9999 is 1.
Jun 24, 2009 5:57 AM #446851
Hey, what's going on. I posted the proof. It's done.
It's not just "generally agreed upon". It's fact. To reiterate my initial statement, I posted the proof.
Quote from Dragon⁰⁷⁷It is generally agreed upon in the mathematic community that .9999... is 1.
It's not just "generally agreed upon". It's fact. To reiterate my initial statement, I posted the proof.
Jun 24, 2009 6:00 AM #446853
Quote from RealHey, what's going on. I posted the proof. It's done.
It's not just "generally agreed upon". It's fact. To reiterate my initial statement, I posted the proof.
Its not over till the fat lady sings.
Jun 24, 2009 6:01 AM #446856
Quote from dr.sassyIts not over till the fat lady sings.
She did. That's why it's called a proof. A mathematical proof proves a mathematical statement to be true. End of the line. No argument will trump it.
Jun 24, 2009 8:06 AM #446904
Here's another attempt at proving this. Methinks it's irrational to try and compute an infinite value. 6^infinity = null because you will never finish computing that. Same idea with 10*0.999 to infinity and beyond.
Jul 19, 2009 2:22 AM #462716
0.99 recurring is ..........................................................................................................................1
As closest as possible, 0.99 (or 0.9999999999999999999999999999999999999999999 to infinity) is ..........................................................................................................................1
But that only depends on HOW you calculate the recurring of 0.99. Actually, 0.99 recurring is sometimes projected by others as not 1 because they didn't round the number and had gone to:
As closest as possible, 0.99 (or 0.9999999999999999999999999999999999999999999 to infinity) is ..........................................................................................................................1
But that only depends on HOW you calculate the recurring of 0.99. Actually, 0.99 recurring is sometimes projected by others as not 1 because they didn't round the number and had gone to:
As closest as possible, 0.99 (or 0.9999999999999999999999999999999999999999999 to infinity) is
Jul 19, 2009 2:45 AM #462722
It's called a rounding error.
/thread.
/thread.